modulo
modulo
1. Modulo crypting / decrypting program by me and my classmate.
(译)：模crypting /解密程序由我和我的classmate.
2. 13 and 28 are congruent modulo 5.
13和28 对模5来说是同余的。
3. 18 is congruent to 42 modulo 12 because both 18 and 42 leave 6 as a remainder when divided by 12.
18和42在对模数12同余，因为当18和42被12整除都有6作为余数
4. Keywords L_1 modulo deconvolution;location;restriction;reflection coefficient;seismic wavelet;wavelet estimation;
1模反褶积;位置;约束;反射系数;地震子波;子波估计;
5. Calculate (base raised into power exp) modulo mod.If exp is negative， result is undefined.
计算 base 的 exp 次幂 对 mod 取模的结果。
6. Calculation of Total Energy and Bulk Modulo for Bl-MoN and Bl-WN Crystals
B1结构MoN和WN晶体的总能及体弹性模量的计算
7. Bernoulli Numbers Modulo 2~r and 3~r
Bernoulli数模2~r和3~r的同余式
8. WANG Ling-li, CHEN Xie-xiong, WU Xun-wei.Modulo subtraction and modulo division in composite multivalued modulo-algebra[J].Acta Electronic Sinica, 1998, 26(5): 17-20.
[1]王伶俐, 陈偕雄, 吴训威. 模为合数时多值模代数的模减与模除运算[J]. 电子学报, 1998, 26(5): 17-20.
9. The remainder from a division of a number by another number. Fox example, the residue for 58 modulo 8 is 2.
一个数被另一个数N除时所得的余数。例如,58模8的余数是2。
10. a Chinese gambling game; a random number of counters are placed under a bowl and you gamble on how many will be left (0 or 1 or 2 or 3) modulo 4.
一种中国式的游戏；一个任意的数字被放在一个碗下并且你赌。
11. An algorithm of dynamic password system based on square modulo
一种基于平方剩余的动态口令算法
12. A Fast Algorithm Suited Embedded Environment for Multiplicative Inverse of a Modulo
一种快速适合嵌入式环境的求模逆元算法
13. Generally, this problem is reduced to quadratic residue problem of modulo a big prime number. But this reduction is not applicable to Optimal Extension Fields (OEF) .
一般而言，该问题归结为模大素数的二次剩余问题，但这种归结不能用于最优扩域OEF。
14. To simplify reduction modulo, special polynomials are used to generate finite field GF(2m), such as AOP (all one polynomials) and trinomials.
为了简化模不可约多项式f(x)运算,采用特殊多项式AOP(allonepolynomials)和三项式,产生有限域GF(2m)。
15. I principali prodotti sono:-colore unico modulo esterno e mezzo, due-tono semi-modulo esterno, i prodotti a LED.
主要产品有：单色半户外模组、双色半户外模组、发光二极管等产品。
16. Example: My physical portion that hits for 2000 is reduced to 1000.The Shadow part should then hit for 1000 (modulo bonuses) and not 500 or whatever.
举例而言：如果我的物理伤害打出了2000伤害，因目标的伤害减免被抵消掉一半，那么我的暗影伤害部分应打出1000点伤害，并不会再被减少一半；
17. two's complement modulo techniques
二进制补码取模
18. Use unsigned types only when you need modulo arithmetic or very very large numbers.
仅在你需要模算术或需要很大很大的数字时，才使用无符号类型。
19. However the time-consuming modulo exponentiation computation, which has always been the bottle-neck of RSA, restricts its wider application.
但该算法所采用的幂剩余计算会耗费太多的时间，一直是制约其广泛应用的瓶颈。
20. Fondata nel 2002, gli indirizzi studenti nel parco commerciale. Sviluppo professionale, impianti di produzione e dei veicoli corrispondenti al veicolo modulo di controllo intelligente.
公司成立于2002年4月份，地址在留学人员创业园。专业研制、生产与整车厂配套的车用智能控制模块。
21. ON THE MODULO 2 IMBEDDING CLASS OF TRIANGULABLE COMPACT MANIFOLDS
关于可三角剖分的紧致流形的模2示嵌类
22. 9.The fmod() function divides x by y and returns the remainder (modulo) of the division.
函数的作用是：返回通过除法求得的浮点数余数。
23. The operation in protocol was simple and fast because only modulo addition and modulo multiplication were involved.
协议中只含模加与模乘运算，运算简单、快速。
24. modulo operation
取模
25. Keywords Trusted Platform Module;Trusted Computing;Security Chip;Security API;Cryptographic protocol;Automatic Reason;Modulo Inverse;Monitor Method;CA （Certificate Authority）;
可信平台模块;可信计算;安全芯片;安全API;密码学协议;自动推理;模逆元算法;监控方法;认证中心（CA）;
26. satisfiability modulo theories (SMT)
可满足性模理论
27. 13 and 28 are congruent modulo 5.13
和28对模5来说是同余的。
28. Since the % character is used extensively by the macro preprocessor, you should ensure that both the signed and unsigned modulo operators are followed by white space wherever they appear.
因为%被宏预处理器广泛使用,你要确保有符号或无符号求余运算符应该紧跟着空格。
29. representation of graph modulo n
图的模n表示
30. In a modulo check, the number by which the summed digits are divided
在模数检验法中,一个和数用某个数来除,其中的除数称为模数。
31. In a modulo check,the number by which the summed digits are divided.
在模数检验法中，一个和数用某个数来除，其中的除数称为模数。参阅modulocheck。
32. Basilico_S_n_c_ [Rho, MI] Ditta di accessori per macchine tessili presenta il profilo, i prodotti, le aree operative e le applicazioni industriali. Modulo richiesta informazioni.
地区/亚洲/中国/广东/深圳/商业与经济/制造业-深圳建鸿来实业有限公司生产塑胶制品、弹簧及系列五金制品，含公司简介及厂房介绍。
33. ANALYSIS OF SHORT-TERM POWER SYSTEM DISTURBANCE BASED-ON MODULO MAXIMUM PRINCIPLE AND ENERGY DISTRIBUTION CURVE OF WAVELET TRANSFORM
基于小波变换模极大值原理和能量分布曲线的电力系统短期扰动分析
34. Research on digital watermark algorithm based on modulo
基于模运算的数字水印算法研究
35. Multiscale boundary detection is equivalent to searching out the local ex-tremum of wavelet transform modulo of image.
多尺度边缘检测等价于寻找图像的小波变换模局部极值。
36. Archia_S_r_l_ [Massafra, TA] Allestimenti fieristici. Presentazione delle strutture realizzate e dei servizi offerti. Modulo per contatti.
宁波市江东区经贸合作网投资指南、介绍招商项目及企业。
37. number class modulo N
对模N的同余类
38. Keywords wavelet transform;scale space;singular point;boundary detection;gradient vector;modulo;
小波变换;尺度空间;奇性点;边缘检测;梯度矢量;模;
39. Faenza_Araldica Laboratorio di arte ceramica faentina: riproduzione figure e stemmi medioevali, con modulo contatti e vendita online.
山东香飘九州饮食文化传播集团提供各种地方风味小吃的加盟连锁企业。
40. Spread spectrum was conducted first, and then it was embedded into watermark by means of integer modulo.
嵌入水印时，先对水印信息进行扩频，再利用基于模运算的方法嵌入水印。
41. modulo two sum gate
异门
42. elastic modulo
弹性模数
43. recycling modulo n counter
循环n模计数器
44. We can try and solve congruences modulo pn for higher and higher value of n.
我们可以对越来越大的n去试解mod pn的同余式。
45. I'm pretty happy with the current state of tanking, modulo polishing up a few bits here and there.
我们的目标之一是让玩家在组队的时候有更大的灵活性。
46. So if we assign 1 to an 8-bit unsigned char the resulting value will be 255 which is 1 modulo 256.
所以，如果把-1赋给8位的unsignedchar，那么结果是255，因为255是-1对256求模后的值。
47. modulo two addition
按位加
48. count modulo n
按模n计数
49. modulo operator
按模运算符
50. In the paper,a combined number generator based on the method of Mersenne Twister and prime modulo multiplicative linear congruence generators is proposed.
提出基于Mersenne Twister法和素数模乘同余法的随机数组合发生器。
51. swing modulo scheduling
摆动模调度
52. This paper analyses the coupling wastage in columniform wave guide gas laser, and gives the function between the coupling wastage of laser guide modulo EH11 and the position and radius of reflector.
摘要分析了圆柱形波导气体激光器中的耦合损耗，给出了最低阶波导模EH11的耦合损耗与反射镜位置、曲率半径的函数关系。
53. multiplication modulo
放大系数
54. Hence, an improved scheme based on square root modulo composites is proposed and the security drawback in W?
文章基于模合数二次剩余问题，提出了一种改进的方案，克服了W?
55. Class to perform a modulo operation on the hash code returned by the.
方法返回的哈希代码执行求模操作。
56. Pc_Zoom [Palermo] Si occupa di web, software, multimedia ed informatica in genere. Modulo per contatti ed area riservata per utenti registrati.
无忧网络技术站包括黑客软件，黑客教程，技术文档，网络安全动态，安全产品，软件工具等信息。
57. The numerals sum of irreducible proper fraction a/3n+2 is 9(t-1)/2+r,where t is the period of a/3n+2 and r is the least non-negative residue of a modulo 9.If the period of 1/p equal to p-1 or (p-1)/2,then p is a prime.
既约真分数a/3n+2的数码和为9(t-1)/2+r,这里t是a/3n+2的周期,r是a模9的最小非负剩余. 如果1/p的周期等于p-1或(p-1)/2,那么p是一个素数.
58. 2BinRome - Illustra le camere a disposizione con immagini, modulo per prenotare, servizi offerti ed ubicazione.
易易工作室-各种在线工具，站长网志，以及多个应用项目。
59. is the multiplication operator. / and // are both division operators: / is unsigned division and // is signed division. Similarly, % and %% provide unsigned and signed modulo operators respectively.
是乘运算符。/和//均是除运算符：/用于无符号数，而//用于有符号数。同样%和%%用于无符号和有符号数的求余运算。
60. More on Solving Equations Modulo Primes
更多关于解模为质数的方程
61. Finally, we put forward the concept of differential characteristic set modulo with respect to a polynomial and present the properties of the characteristic set.
最后，对微分特征列集理论进行了推广，给出了微分多项式系统的模微分特征列集的概念，并研究了其具有的性质。
62. Minimize total tardiness of the parallel machine with modulo constrain
有模具约束的平行机台最小拖期和调度问题
63. This paper classifies the RTL hybrid satisfiability solving methods into two classes: One is based on Satisfiability Modulo Theories (SMT), and the other is based on circuit structure search.
本文将RTL混合可满足性求解方法分为基于可满足性模理论(SMT)和基于电路结构搜索两大类。
64. The Checksum Word contains the twos complement of the modulo 256 sum of the.
校验字包含两个数据信息的和与256的模的两个补码。
65. Modulo (finds the remainder after division)
模(除之后的余数)
66. Addition on modulo 2n
模2n加
67. modulo 2 addition
模2加法
68. modulo 2 adder
模2加法器
69. modulo 2 arithmetic
模2运算
70. transfer check modulo 3
模3传送检验
71. pancyclic modulo k
模k泛圈
72. residue class modulo m
模m剩余类
73. fontal characteristic of modulo m
模m的原特征
74. characteristic of modulo m
模m的特征
75. curtate remainder series of modulo m
模m的缩系
76. modulo N
模N
77. modulo n residue
模n余数
78. irreducible polynomials over the ring of residues modulo n
模n剩余类环上的不可约多项式
79. modulo - n adder
模n加法器
80. modulo n check
模n检验 按模数N校验
